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Question

NaNO3 is converted to KNO3 by the reaction: NaNO3(aq)+KCl(aq)KNO3(aq)+NaCl(s).
In the above equilibrium, which is the least soluble in hot water?

A
NaNO3
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B
KCl
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C
KNO3
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D
NaCl
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Solution

The correct option is D NaCl
Reaction: NaNO3(aq)+KCl(aq)KNO3(aq)+NaCl(s)
In this reaction, NaCl is formed as a solid product and it also forms precipitate due to which reaction moves forward.
Here, it is observed that NaCl is least soluble amongst all reagents.

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