Question

NaNO3 does not react with dilute solution of H2SO4.Why?

Answer 1

Dear Student,


$$\begin{gathered} {\mathrm{HNO}}_3\mathrm{is}\mathrm{a}\mathrm{stronger}\mathrm{acid}\mathrm{than}{\mathrm{H}}_2{\mathrm{SO}}_4,\mathrm{therefore}{\mathrm{HNO}}_3\mathrm{cannot}\mathrm{be}\mathrm{formed}\mathrm{by}\mathrm{reaction}\mathrm{of}{\mathrm{NaNO}}_3\mathrm{and}{\mathrm{H}}_2{\mathrm{SO}}_4 \\ 2{\mathrm{NaNO}}_3+\hspace{0.17em}{\mathrm{H}}_2{\mathrm{SO}}_4\to 2{\mathrm{HNO}}_3+{\mathrm{Na}}_2{\mathrm{SO}}_4 \\ \mathrm{Hence},{\mathrm{NaNO}}_3\mathrm{doesnot}\mathrm{react}\mathrm{with}{\mathrm{H}}_2{\mathrm{SO}}_4 \end{gathered}$$