Question

${\mathrm{Na}}^{+}$ has completely filled $\mathrm{K}$ and $\mathrm{L}$ shells. Explain.

Answer 1

Electronic configuration:-

1. In quantum chemistry, the electronic configuration is actually the distribution of the electrons in the orbitals of an atom.
2. Sodium is basically a member of the alkali metal family.
3. A positive ion or cation is generally formed by the losing of electrons.
4. Sodium atom ($\mathrm{Na}$) has atomic number = 11
5. So, the number of protons and electrons Sodium atom ($\mathrm{Na}$) has = 11 each.
6. So, the electronic configuration of $\mathrm{Na}$ atom in the different shells (K, L, M) = 2, 8, 1.
7. So, if Sodium atom loses 1 electron to become (${\mathrm{Na}}^{+}$), then the electronic configuration would be (K, L) = 2, 8.
8. Hence, K and L shells are completely filled, which is (2, 8) and this is a electronic configuration.