Naresh Kumar drives his car to his office with the speed of $40$ km per hour and returns along the same route with the speed of $60$ km per hour. Find his average speed for the entire round trip.

50 k m / h

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54 k m / h

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48 k m / h

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44 k m / h

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Solution

The correct option is D $48 k m / h$
Let the distance be $= x$
time taken if speef $40 k m / h r = \frac{x}{40}$
time taken in return $= \frac{x}{60}$
total distance $= 2 x$
Average speed $= \frac{2 x}{(\frac{x}{40}) + (\frac{x}{60})} => \frac{2 x \times 120}{(3 x + 2 x)} = \frac{2 x \times 120}{5 x} = 48 k m / h r$

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Naresh Kumar drives his car to his office with the speed of 40 km per hour and returns along the same route with the speed of 60 km per hour. Find his average speed for the entire round trip.

The correct option is D 48km/hLet the distance be =xtime taken if speef 40km/hr=x40time taken in return =x60total distance =2xAverage speed =2x(x40)+(x60)=>2x×120(3x+2x)=2x×1205x=48km/hr

Naresh Kumar drives his car to his office with the speed of $40$ km per hour and returns along the same route with the speed of $60$ km per hour. Find his average speed for the entire round trip.