Naresh walked $2 k m 35 m$ in the morning and $1 k m 7 m$ in the evening. How much distance did he walk in all?

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Solution

Given that:
Distance walked by Naresh in the morning $= 2 k m 35 m$
Distance walked by Naresh in the evening $= 1 k m 7 m$
Convert the given unit of $k m$ into $m$
We know that,
$1 k m = 1000 m$
Now,
Distance walked by Naresh in the morning $= 2 k m 35 m = (2 \times 1000) m + 35 m = 2035 m$
Distance walked by Naresh in the evening $= 1 k m 7 m = (1 \times 1000) m + 7 m = 1007 m$
Total distance walked by Naresh $=$ Distance walked by Naresh in the morning $+$ Distance walked by Naresh in the evening
$=$ $2035 m + 1007 m$
$=$ $3042 m$
Also, $3042 m = (3 \times 1000) m + 42 m = 3 k m 42 m$
Hence, Total distance did Naresh walk is $3 k m 42 m$

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