wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Natural length of a spring is 60cm and its spring constant is 4000N/m. A mass of 20kg is hung from it. The extension produced in the spring is (take g = 9.8 m/s2):

A
4.9cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.49cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
9.4cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.94cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 4.9cm
Given, l=60 cm=60×102m
m=20 kg,k=4000 N/m
The weight hung from the spring =mg=20×9.8=196 N
Let x be the extension produced in spring.
Now, force applied by the spring = downward force on the spring
kx=mgx=mgk
or, x=20×9.84000=0.049 m=4.9 cm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon