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Standard XII

Chemistry

Mole Concept

Naturally occ...

Question

Naturally occuring lithium consists of two isotopes whose atomic weights are 6.015 u and 7.016 u. The atomic weight of natural lithium is 6.491 u. The percentage by number of atoms of each isotpe in natural lithium is and respectively.

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Solution

Let the fraction of Li-6.015 be x.
So, the fraction of Li-7.016 will be 1-x.
According to the question,
$60.015 x + 7.016 (1 - x) = 6.941$
$\Rightarrow 1.001 x = 0.075 \Rightarrow x = 0.07493$
So, the percentage of Li-6.015 is 7.493% and the percentage of Li-7.016 is 92.507%

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Naturally occuring lithium consists of two isotopes whose atomic weights are 6.015 u and 7.016 u. The atomic weight of natural lithium is 6.491 u. The percentage by number of atoms of each isotpe in natural lithium is and respectively.

Let the fraction of Li-6.015 be x. So, the fraction of Li-7.016 will be 1-x. According to the question, 60.015x+7.016(1−x)=6.941 ⇒1.001x=0.075⇒x=0.07493 So, the percentage of Li-6.015 is 7.493% and the percentage of Li-7.016 is 92.507%

Let the fraction of Li-6.015 be x.
So, the fraction of Li-7.016 will be 1-x.
According to the question,
$60.015 x + 7.016 (1 - x) = 6.941$
$\Rightarrow 1.001 x = 0.075 \Rightarrow x = 0.07493$
So, the percentage of Li-6.015 is 7.493% and the percentage of Li-7.016 is 92.507%