Atomic no . of Neon Ne is 10
By emission of two α-α−particles, atomic no . will be reduced by 4. Atomic no.of unknown element will be
Z= 10−4 = 6Z=10−4=6
Similarly, mass no .of unknown element will be
A=22−2×4 =14A=22−2×4=14
The unknown nucleus is carbon (A=14, Z=6)