Neelam has a beautiful rectangular painting on a wall in herdoll house. The painting is painted on a wooden block. Thepainting occupies 0.2 % area of the wall. If the thickness ofthe painting is 8 cm and the volume of the painting is 4480cm3
, what is the area of the wall?

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Solution

$V o l u m e = A r e a \times h e i g h t . H e r e h e i g h t = 8 c m a n d v o l = 4480 c m c u b e A r e a = V o l u m e / h e i g h t = 4480 / 8 = 560 c m s q . A r e a o f p a i n t i n g = . 2 % o f w a l l L e t A r e a o f w a l l = x c m s q . N o w a c c . t o q u e s t i o n \frac{. 2}{100} \times x = 560 \Rightarrow x = 560 \times 500 = 280000 c m s q .$

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Neelam has a beautiful rectangular painting on a wall in herdoll house. The painting is painted on a wooden block. Thepainting occupies 0.2 % area of the wall. If the thickness ofthe painting is 8 cm and the volume of the painting is 4480cm3, what is the area of the wall?

Volume = Area × height . Here height = 8cm and vol = 4480 cm cubeArea = Volume / height = 4480 / 8 = 560 cm sq.Area of painting = .2% of wall Let Area of wall = x cm sq . Now acc. to question .2100×x = 560 ⇒x = 560 ×500 = 280000 cm sq.

Neelam has a beautiful rectangular painting on a wall in herdoll house. The painting is painted on a wooden block. Thepainting occupies 0.2 % area of the wall. If the thickness ofthe painting is 8 cm and the volume of the painting is 4480cm3
, what is the area of the wall?