Question

Neelesh leaves for his office from his house. He walks towards East. After moving a distance of 20m, he turns towards South and walks 10m. Then he walks 35m towards the West and further 5m towards the North. He then turns towards East and walks 15m. What is the straight distance in 'm' between his initial and final positions?

• A. 0
• B. 5
• C. 10
• D. cannot be determined

Answer 1

The correct option is B 5


$Clearly,DC=AB+EF$

$therefore\text{F is in line with A.}$

$Also,AF=(BC-DE)=5m.$

$\text{So, Neelesh is 5 m away from his initial position.}$