Question

Neeta and Meeta are friends. They were both born in 2003. What is the probability that they have the

(i) Same Birthday (ii) Different Birthdays

• A. i) $\frac{1}{365}$ ii) $\frac{2}{365}$
• B. (i) $\frac{1}{365}$ (ii) $\frac{364}{365}$
• C. i) $\frac{2}{365}$ ii) $\frac{1}{360}$
• D. i) $\frac{3}{365}$ ii) $\frac{1}{366}$

Answer 1

The correct option is B

(i) $\frac{1}{365}$ (ii) $\frac{364}{365}$

There are 365 days in the year 2003 since its not a leap year

Neeta and Meeta can have any of the days out of 365 days as their birthday

(i)Let E be the event Neeta and Meeta have the same birthday, then the number of favourable outcomes to the event E = 1

$\therefore$ P(E) = $\frac{1}{365}$

(i)P( Neeta and Meeta have different birthdays) = P (not E )

P (not E ) = 1 - P(E)

= 1 - $\frac{1}{365}$

= $\frac{364}{365}$