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Byju's Answer
Standard XII
Mathematics
And
Negation of t...
Question
Negation of the Boolean expression
p
⇔
(
q
⇒
p
)
is
Open in App
Solution
p
⇔
(
q
→
p
)
∼
(
p
⇔
(
q
⇔
p
)
)
≡
∼
[
(
∼
p
∨
(
q
→
p
)
)
∧
(
p
∨
∼
(
q
→
p
)
)
]
≡
∼
[
(
∼
p
∨
(
∼
q
∨
p
)
)
∧
(
p
∨
∼
(
∼
q
∨
p
)
)
]
≡
∼
[
T
∧
(
p
∨
(
q
∧
∼
p
)
)
]
≡
∼
[
(
p
∨
q
)
∧
(
p
∨
∼
p
)
]
≡
∼
[
(
p
∨
q
)
∧
T
]
≡
∼
p
∧
∼
q
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2
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