Negation of the statement - p- q- r is

∼[∼ p → ( q ∨ r ) ]=p ( ∼ q ∼ r ) ...

Negation of t...

Question

Negation of the statement $\sim p \to (q \lor r)$ is

$p \to\sim (q \lor r)$

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$p \lor (q \land r)$

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$p \land \sim q \land \sim r$

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$p \land (q \lor r)$

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Solution

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