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Standard VIII

Mathematics

Solving Linear Equations Using Transpose of Terms

Neglecting ai...

Question

Neglecting air resistance, the upward velocity of the water in the stream of a particular fountain is given by the formula $v = - 32 t + 28$ , where $t$ is the number of seconds after the water leaves the fountain. While going upward, the water slows down until at the top of the stream, the water has a velocity of $0$ feet per second. How long does it take a droplet of water to reach the maximum height?

0.825

seconds

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0.925

seconds

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0.875

seconds

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0.975

seconds

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Solution

The correct option is C $0.875$ seconds
Given, $v = - 32 t + 28$
It is mentioned that at the maximum height, the velocity of water is $0$ feet per second.
Therefore, final velocity $(v) = 0$ .
$\Rightarrow 0 = - 32 t + 28$
$\Rightarrow 32 t = 28$
$\Rightarrow t = \frac{28}{32} = 0.875$ seconds

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The correct option is C 0.875 secondsGiven, v=−32t+28It is mentioned that at the maximum height, the velocity of water is 0 feet per second.Therefore, final velocity (v)=0. ⇒0=−32t+28⇒32t=28 ⇒t=2832=0.875 seconds

The correct option is C $0.875$ seconds
Given, $v = - 32 t + 28$
It is mentioned that at the maximum height, the velocity of water is $0$ feet per second.
Therefore, final velocity $(v) = 0$ .
$\Rightarrow 0 = - 32 t + 28$
$\Rightarrow 32 t = 28$
$\Rightarrow t = \frac{28}{32} = 0.875$ seconds