Neglecting friction, what is the velocity of center of mass of the system, after collision?

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Solution

$v_{c m} = \frac{m_{1} v_{1} + m_{2} v_{2} + m_{3} v_{3}}{m_{1} + m_{2} + m_{3}}$
$= \frac{(3) (0.2) - (6) (0.1) + 3 (0.4)}{3 + 6 + 3}$
$= 0.1 m / s$ (towards right)

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Neglecting friction, what is the velocity of center of mass of the system, after collision?

vcm=m1v1+m2v2+m3v3m1+m2+m3 =(3)(0.2)−(6)(0.1)+3(0.4)3+6+3 =0.1m/s (towards right)

$v_{c m} = \frac{m_{1} v_{1} + m_{2} v_{2} + m_{3} v_{3}}{m_{1} + m_{2} + m_{3}}$
$= \frac{(3) (0.2) - (6) (0.1) + 3 (0.4)}{3 + 6 + 3}$
$= 0.1 m / s$ (towards right)