Question

Neha walks form the house 160 m north and there 630 m west to visit her friend's house. We coming back, she walks diagonally from her friend's house to her house. How much distance does cover while returning ?

Answer 1

Actually it is forming a right angle triangle here we have to find the hypotenuse and other two legs are $160$ m and $630$ m so

$O{B}^2=O{A}^2+A{B}^2$

$\Rightarrow O{B}^2=(160{)}^2+(630{)}^2$

$=25600+396900$

$=422500$

$\Rightarrow OB=650m$