Neon gas is generally used in sign boards. If it emits strongly at 616 nm, calculate:

(C) Energy of quantum

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Solution

Frequency of emission (v) = $4.87 \times 10^{14} s^{- 1}$ {from part 1}
Energy of quantum (E) = hv
$= (6.626 \times 10^{- 34} J s) \times (4.87 \times 10^{14} s^{- 1})$

$= 3.227 \times 10^{- 19} J$

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Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate (a) the frequency of emission, (b) distance traveled by this radiation in 30 s (c) energy of quantum and (d) number of quanta present if it produces 2 J of energy

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Neon gas is generally used in sign boards. If it emits strongly at 616 nm, calculate:​ (C) Energy of quantum

Frequency of emission (v) = 4.87×1014s−1 {from part 1} Energy of quantum (E) = hv =(6.626×10−34Js)×(4.87×1014s−1) =3.227×10−19J

Neon gas is generally used in sign boards. If it emits strongly at 616 nm, calculate:

(C) Energy of quantum

Frequency of emission (v) = $4.87 \times 10^{14} s^{- 1}$ {from part 1}
Energy of quantum (E) = hv
$= (6.626 \times 10^{- 34} J s) \times (4.87 \times 10^{14} s^{- 1})$

$= 3.227 \times 10^{- 19} J$