Question

Net work done by $1$ mole of ain ideal gas in complete cycle shown below is:

$(ln2=0.7)$

• A. $440$R
• B. $1120$R
• C. $-440$R
• D. none of these

Answer 1

The correct option is D none of these

$W_{PQ}=RTln\left(\frac{V_2}{V_1}\right)$

$=R\left(400\right)ln\left(\frac{10}{5}\right)=280R$

$W_{RS}=RTln\left(\frac{V_2}{V_1}\right)=R\left(800\right)ln\left(\frac{5}{20}\right)=-1120R$

At constant volume work done is zero.

$\therefore$ Net work done by the gas

$=W_{PQ}+W_{RS}$

$=280R+(-1120R)$

$=-680R$ .