Question

# Neutron decay in free space is given as follows$$_{ 0 }{ n }^{ 1 }\longrightarrow _{ 1 }{ H }^{ 1 }+_{ 1 }{ e }^{ 0 }+$$[  ]Then the parenthesis [  ] represents a

A
neutrino
B
photon
C
antineutrino
D
graviton

Solution

## The correct option is B antineutrinoSince the charge is already conserved in the decay process, proton cannot be ejected.To conserve the spin angular momentum of the initial neutron particle, an antineutrino (chargeless) is ejected.Physics

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