Newton's law of cooling is applied in laboratory for the determination of the

Specific heat of gases

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Latent heat of gases

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Specific heat of liquids

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Latent heat of liquids

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Solution

The correct option is D Specific heat of liquids
When a body with mass 'm' and specific heat 's' cools, the rate of loss of heat is given by $\frac{d Q}{d t}$ = $- m s$ $\frac{d θ}{d t}$
where, $θ$ is the temperature of the body
$t$ is time

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Newton's law of cooling is applied in laboratory for the determination of the

The correct option is D Specific heat of liquidsWhen a body with mass 'm' and specific heat 's' cools, the rate of loss of heat is given by dQdt = −msdθdt where, θ is the temperature of the body t is time

The correct option is D Specific heat of liquids
When a body with mass 'm' and specific heat 's' cools, the rate of loss of heat is given by $\frac{d Q}{d t}$ = $- m s$ $\frac{d θ}{d t}$
where, $θ$ is the temperature of the body
$t$ is time