$N H_{2} - N H_{2}$ serves as

Bridging ligand

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Monodentate ligand

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Chelating ligand

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Both (a) and (b).

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Solution

The correct option is D Both (a) and (b).
$N H_{2} - N H_{2}$ behaves both as bridging and monodentate ligand. It is a bidentate ligand having two $- N H_{2}$ donating groups. When both the lone pair of electrons are donating to metal atom then it behaves as a bridging ligand

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Similar questions

(N H_{2}^{-}, C H_{3} C O O^{-}, O H^{-})

R C H O + {N H}_{2} {N H}_{2} \to R C H = N - {N H}_{2}

N H_{2} - N H_{2}

N H_{3}

C H_{3} C H O

N H_{2} - N H_{2}

C H_{3} - C H = N - N H_{2}

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