You visited us 1 times! Enjoying our articles? Unlock Full Access!

Depression in Freezing Point

NH 2 COONH 4 ...

Question

$N H_{2} C O O N H_{4} (s) ⇌ 2 N H_{3} (g) + C O_{2} (g) .$
If the equilibrium pressure is 3x bar at temperature 'T' where 'x' is the degree of dissociation, then $Δ_{r} G^{\circ}$ would be:

- R T l n 9 - 3 R T l n X

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R T l n 4 - 3 R T l n x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 3 R T l n x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D None of these
Moles of ammonia and carbon dioxide at equilibrium would be $2 x, x$ respectively, total moles being $3 x$ . The partial pressure of these would be: $\frac{2 x}{3 x} \times 3 x, \frac{x}{3 x} \times 3 x$ i.e. $2 x, x Δ G^{\circ} = - R T I n K_{p}; K_{p} = p_{N H_{3}}^{2} \times p_{C O_{2}} K_{p} = (2 x)^{2} x = 4 x^{3}$
$Δ G^{\circ} = - R T l n (4 x^{3})$
$Δ G^{\circ} = - R T l n 4 - 3 R T l n x$

Suggest Corrections

Similar questions

N H_{2} C O O N H_{4} (s) ⇌ 2 N H_{3} (g)

3 X

Δ G^{\circ}

N H_{2} C O O N H_{4} (s) ⇌ 2 N H_{3} (g) + C O_{2} (g) .

N H_{3}

N H_{2} C O O N H_{4} (s) ⇌ 2 N H_{3} (g) + C O_{2} (g)

N H_{3}

N H_{2} C O O N H_{4} (s) ⇌ 2 N H_{3} (g) + C O_{2} (g)

5

K_{p}

N H_{2} C O O N H_{4} (s) ⇌ 2 N H_{3} (g) + C O_{2} (g)

3 a t m

1000 K

K_{p}

Join BYJU'S Learning Program