$N H_{3} (a q) + H_{2} C O_{3} (a q) ⇋ N H_{4}^{+} (a q) + H C O_{3}^{-} (a q)$

In the given reaction, $N H_{4}^{+}$ acts as :

indicator

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hydrate

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acid

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base

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salt

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Solution

The correct option is C acid
$N H_{3}$ is base. Ammonium ion $N H_{4}^{+}$ is a conjugate acid. The conjugate acid-base pair differ by a proton only.

Thus ammonium ion can lose a proton to form ammonia.

$N H_{4}^{+} \to N H_{3} + H^{+}$

Hence, the correct option is C.

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Similar questions

N H_{3} (a q) + H_{2} C O_{3} (a q) ⟶ N H_{4}^{+} (a q) + H C O_{3}^{-} (a q), N H_{4}^{+} (a q)

{N H}_{4}^{+} (a q) + {C N}^{-} (a q) ⇌ H C N (a q) + {N H}_{3} (a q)

N H_{3 (a q)} + H_{2} O_{(l)} = N H_{4}^{+} (a q) + O H^{-} (a q)

{NH}_{3} (aq) + H_{2} O (l) \to {NH}_{4}_{4}^{+} (aq) + {OH}^{-} (aq)

Oxidant and Reductanct in the following reactions are respectively

$10 H^{+} (a q) + 4 Z n (s) + N O_{3}^{-} (a q) \to 4 Z n^{2 +} (a q) + N H_{4}^{+} (a q) + 3 H_{2} O (l)$

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