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Haber Bosch Process

NH3 can't be ...

Question

$N H_{3}$ can't be obtained by :

heating of

N H_{4} N O_{3}

N H_{4} N O_{2}

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heating

N H_{3} C I

(N H_{4})_{2} C O_{3}

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heating of

N H_{4} N O_{3}

with

N a O H

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reaction of

A I N

M g_{3} N_{2}

C a C N_{2}

with

H_{2} O

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Solution

The correct option is B heating of $N H_{4} N O_{3}$ or $N H_{4} N O_{2}$
Reactions are:
$N H_{4} N O_{3} \to N_{2} O + H_{2} O$
$N H_{4} N O_{2} \to N_{2} + H_{2} O$
$N H_{4} C l \to N H_{3} + H C l$
$N H_{4} N O_{3} (a q) + N a O H (s) \to N H_{3} (g) + H_{2} O (l) + N a N O_{3} (a q)$
$C a C N_{2} + 3 H_{2} O \to C a C O_{3} + N H_{3}$

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