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Question

+NH3CH(R)CO2H has its Ka1=107. The isoelectric point of the α-amino acid occur at pH = 8.2 Hence pKa2 of the conjugate acid of α-amino acid is equal to:

A
9.4
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B
1.2
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C
7.6
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D
2.4
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Solution

The correct option is D 9.4
Isoelectric point is given by,
pI=pKa1+pKa22

Ka1=107,pI=8.2

pKa1=logKa1

pKa1=log107=7

8.2=pKa1+pKa22=7+pKa22

16.4=7+pKa2

pKa2=9.4

Option A is correct.

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