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Standard XII

Chemistry

Atomic Size and Electronegativity

NH3 has much ...

Question

$N H_{3}$ has much higher boiling point than $P H_{3}$ because :

N H_{3}

has much higher molecular mass.

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N H_{3}

forms hydrogen bonds.

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N H_{3}

contains ionic bonds while

P H_{3}

contains covalent bonds.

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N H_{3}

undergoes umbrella inversion.

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Solution

The correct option is B $N H_{3}$ forms hydrogen bonds.
Due to formation of hydrogen bonds, $N H_{3}$ have much higher boiling point than $P H_{3}$ .

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Similar questions

Q. Which of the following orders is/are correct?

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

(Boiling point)

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

(Thermal stability)

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

(Basic character)

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

(Bond angle)

P H_{3}

has lower boiling point than

N H_{3}

. Why?

Q. Which of the following orders is/are correct?

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

(Boiling point)

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

(Thermal stability)

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

(Basic character)

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

(Bond angle)

Ammonia forms a large number of complexes with transition metal ions. Hybridisation easily explains the case of sigma donation capability of $N H_{3}$ and $P H_{3}$ .
Choose the correct statement from the following:

I	II
$N H_{3}$	$P H_{3}$

The bond angle in

N H_{3}

is larger than, in

P H_{3}

because the

P - H

bonds are longer and the lower electronegativity of P permits electron-density to be displaced towards hydrogen to a greater extent than in the case of

N H_{3}

. Both of these effects diminish the repulsion due to bond-pairs.
If true enter 1, else enter 0.

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NH3 has much higher boiling point than PH3 because :

The correct option is B NH3 forms hydrogen bonds.Due to formation of hydrogen bonds, NH3 have much higher boiling point than PH3.

$N H_{3}$ has much higher boiling point than $P H_{3}$ because :

The correct option is B $N H_{3}$ forms hydrogen bonds.
Due to formation of hydrogen bonds, $N H_{3}$ have much higher boiling point than $P H_{3}$ .