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Byju's Answer

Standard XII

Chemistry

Haber Bosch Process

NH3 is formed...

Question

$N H_{3}$ is formed in the following steps
I. $C a + 2 C \to C a C_{2}$ 50% yield
II. $C a C_{2} + N_{2} \to C a C N_{2} + C$ 100% yield
III. $C a C N_{2} + 3 H_{2} O \to 2 N H_{3} + C a C O_{3}$ 50% yield
To obtain 2 moles $N H_{3}$ , calcium required is:

1 mol

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2 mol

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3 mol

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4 mol

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Solution

The correct option is C 1 mol
It can be easily observed from the reaction given that 1mole of Ca is required to get 2 moles of $N H_{3}$

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Similar questions

N H_{3}

is formed in the following steps,

I

C a + 2 C ⟶ C a C_{2}

(

50 %

yield)

I I

C a C_{2} + N_{2} ⟶ C a C N_{2} + C

(

100 %

yield)

I I I

C a C N_{2} + 3 H_{2} O ⟶ 2 N H_{3} + C a C O_{3}

(

50 %

yield)
To obtain

2

moles of

N H_{3}

, calcium required is :

The product obtained as a result of a reaction of nitrogen with $C a C_{2}$ is

3 C u O + 2 N H_{3} \to 3 C u + 3 H_{2} O + N_{2}

In this reaction

N H_{3}

Q. Urea

(N H_{2} C O N H_{2})

is formed when

C O_{2}

reacts with

N H_{3}

C O_{2} + 2 N H_{3} ⟶ N H_{2} C O N H_{2} + H_{2} O

N H_{3}

and

C O_{2}

are obtained in the following steps:

I

N_{2} + 3 H_{2} 90 % - - \to 2 N H_{3}

I I

C a C O_{3} 50 % - - \to C a O + C O_{2}

Amount of

N_{2}

and

C a C O_{3}

required to produce

60

kg of urea are

X

kg and

Y

kg respectively. The value of

X + Y

(nearest integer value ) is :

Q. In the reaction,

3 C u O + 2 {N H}_{3} ⟶ N_{2} + 3 H_{2} O + 3 C u

the change of

{N H}_{3}

N_{2}

involves:

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NH3 is formed in the following stepsI. Ca+2C→CaC2 50% yieldII. CaC2+N2→CaCN2+C 100% yieldIII. CaCN2+3H2O→2NH3+CaCO3 50% yieldTo obtain 2 moles NH3, calcium required is:

The correct option is C 1 molIt can be easily observed from the reaction given that 1mole of Ca is required to get 2 moles of NH3

$N H_{3}$ is formed in the following steps
I. $C a + 2 C \to C a C_{2}$ 50% yield
II. $C a C_{2} + N_{2} \to C a C N_{2} + C$ 100% yield
III. $C a C N_{2} + 3 H_{2} O \to 2 N H_{3} + C a C O_{3}$ 50% yield
To obtain 2 moles $N H_{3}$ , calcium required is:

The correct option is C 1 mol
It can be easily observed from the reaction given that 1mole of Ca is required to get 2 moles of $N H_{3}$