Question

${NH}_3$ is oxidised to $NO$ by $O_2$ (Air) in basic medium. Number of equivalent of ${NH}_3$ oxidised by $2$ mol of $O_2$ is:

• A. $\frac{8}{5}$
• B. $8$
• C. $7$
• D. $6$

Answer 1

The correct option is A $\frac{8}{5}$

Oxidation of $N{H}_3$ is given by the equation, $4N{H}_3+5O_2⟶4NO+6H_{2}O$

$1$ $mole$ of $N{H}_3$ reacts with $\frac{5}{4}$ $moles$ of $O_2$.

$\therefore$ $2$ $moles$ of $O_2$ reacts with $\frac{2\times 1}{\frac{5}{4}}=\frac{8}{5}$ $moles$ of $N{H}_3$