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Mole Concept

NH 3 is oxidi...

Question

${N H}_{3}$ is oxidised to $N O$ by $O_{2}$ (air) in basic medium. Number of equivalents of ${N H}_{3}$ oxidised by $1$ mole of $O_{2}$ is :

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Solution

$4 N ↑ - 3 H_{3} + 5 O_{2} ⟶ 4 N ↑ + 2 O + 6 H_{2} O$
$1 m o l O_{2} o x i d i s e s \frac{4}{5} m o l o f {N H}_{3}$ $= \frac{4}{5} \times 5 e q u i v a l e n t s o f {N H}_{3} = 4 e q u i v a l e n t s$ .

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