Question

$(N{H}_4{)}_{2}C{r}_2{O}_7$ on heating liberates gas. The same gas will be obtained by :

• A. heating $N{H}_{4}N{O}_2$
• B. heating $N{H}_{4}N{O}_3$
• C. treating $M{g}_3{N}_2$ with $H_{2}O$
• D. heating $H_2{O}_2$ on $NaN{0}_2$

Answer 1

The correct option is A heating $N{H}_{4}N{O}_2$

On heating, $(N{H}_4{)}_{2}C{r}_2{O}_7$ gives, nitrogen gas.

$(N{H}_4{)}_{2}C{r}_2{O}_7\to N_2+C{r}_2{O}_3+4H_{2}O$

(Orange) (Green)

But whenever, $N{H}_{4}N{O}_2$ and $N{H}_{4}N{O}_3$ heated, then nitrogen and nitrogen dioxide gas liberated.

$N{H}_{4}N{O}_2\to N_2+2H_{2}O$

$N{H}_{4}N{O}_3\to N_{2}O+2H_{2}O$

So, the correct option is $A$