Question

$N{H}_{4}CI\left(s\right)$ is heated in a test tube, vapours are brought in contact with red litmus paper, which changes to blue and then to red. it is because of :

• A. formation of $N{H}_{4}OH$ and $HCI$
• B. formation of $N{H}_3$ and $HCI$
• C. greater diffusion of $N{H}_3$ than $HCI$
• D. grater diffusion of $HCI$ than $N{H}_3$

Answer 1

The correct option is C greater diffusion of $N{H}_3$ than $HCI$

$N{H}_{4}Cl\stackrel{\Delta }{\to }N{H}_3+HCl$
First HCl reacts with red litmus and converts it into blue but as diffusion of ammonia is high so after that ammonia reacts with blue litmus and converts back to red.