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Question

NH4Cl crystallizes in a body centred cubic lattice , with a unit cell distance of 387 pm. Calculate the radius of the NH+4 ion if the radius of the Cl ion is 181 pm.

A
608.67 pm
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B
52.67 pm
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C
335.15 pm
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D
154.15 pm
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Solution

The correct option is D 154.15 pm
In a body centred cubic lattice, oppositely charged ions touch each other along the cross-diagonal of the cube.
So,
2r++2r=3a

r++r=3a2

r+=(3×3872 181) pmr+=154.15 pm

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