Question

$N{H}_{4}HS\left(s\right)⟶N{H}_3\left(g\right)+H_{2}S\left(g\right)$
For this reaction relate $\Delta H$ and $\Delta U$.

• A. $\Delta H$ =$\Delta U$
• B. $\Delta H$ > $\Delta U$
• C. $\Delta H$ < $\Delta U$
• D. None of these

Answer 1

The correct option is B $\Delta H$ > $\Delta U$

As we know,
$\Delta H$ =$\Delta U+\Delta n_{g}RT$
here,
$N{H}_{4}HS\left(s\right)⟶N{H}_3\left(g\right)+H_{2}S\left(g\right)$
$\Delta n_g=2$
so,
$\Delta H$ > $\Delta U$