NH 4 HS s - N H 3 g - H 2 S g - If K p -64 atm 2- equilibrium pressure of the mixture is-A- 16 atmB- 8 atmC- 64 atmD- None of the above

Name: JEE - Grade 11 - Chemistry - GOC -1 - Session 14 - W02
Uploaded: 2022-07-04T10:36:42+05:30
Description: The correct option is A 16 atm[ NH_4HS(s) amp; ⇌ amp; NH_3(g) amp; + amp; H_2S(g) amp; K_P = 64 atm^2; ...

The correct option is A 16 atm[ NH_4HS(s) amp; ⇌ amp; NH_3(g) amp; + amp; H_2S(g) amp; K_P = 64 atm^2; ...

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Byju's Answer

Standard XII

Chemistry

Effective Equilibrium Constant

NH 4 HS s ⇌ N...

Question

$N H_{4} H S (s) ⇌ N H_{3} (g) + H_{2} S (g),$ If $K_{p} = 64$ $a t m^{2}$ , equilibrium pressure of the mixture is?

16 atm

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8 atm

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64 atm

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None of the above

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Solution

The correct option is A 16 atm
$\begin{matrix} N H_{4} H S (s) & ⇌ & N H_{3} (g) & + & H_{2} S (g) & K_{P} = 64 a t m^{2} 0 & 0 & 0 a - x & x & x \end{matrix}$
$\Rightarrow K_{P} = [N H_{3}] [H_{2} S] = x^{2}$
$x^{2} = 64 a t m^{2}$
$x = 8 a t m$
total pressure at equilibrium $= 8 + 8 = 16 a t m$

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Similar questions

Q. For

N H_{4} H S (s) ⇌ N H_{3} (g) + H_{2} S (g)

. If

K_{P} = 64 a t m^{2}

. Equilibrium pressure of mixture is:

N H_{4} H S (s) ⇌ N H_{3} (g) + H_{2} S (g),

K_{p} = 64

a t m^{2}

, equilibrium pressure of the mixture is?

N H_{4} H S (s) ⇌ N H_{3} (g) + H_{2} S (g)

What is the

K_{p}

of the reaction if the total pressure at equilibrium is 30 atm?

Q. For the reaction

N H_{4} H S_{(s)} ⇌ N H_{3 (g)} + H_{2} S_{(g)}

, started with

N H_{4} H S_{(s)}

only. observed equilibrium pressure of the mixtures is

1.2

atm at certain temperature, what is the

K_{p}

of the reaction?

Q. For

{N H}_{4} H S (s) ⇌ {N H}_{3} (g) + H_{2} S (g)

the observed,pressure for reaction mixture in equilibrium is 1.12 atm at

106^{0} C

What is the value of

K_{P}

for the reaction?

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Effective Equilibrium Constant

Standard XII Chemistry

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NH4HS(s)⇌NH3(g)+H2S(g), If Kp=64 atm2, equilibrium pressure of the mixture is?

The correct option is A 16 atmNH4HS(s)⇌NH3(g)+H2S(g) KP=64atm2000a−xxx ⇒KP=[NH3][H2S]=x2 x2=64 atm2 x=8 atm total pressure at equilibrium =8+8=16 atm

$N H_{4} H S (s) ⇌ N H_{3} (g) + H_{2} S (g),$ If $K_{p} = 64$ $a t m^{2}$ , equilibrium pressure of the mixture is?

The correct option is A 16 atm
$\begin{matrix} N H_{4} H S (s) & ⇌ & N H_{3} (g) & + & H_{2} S (g) & K_{P} = 64 a t m^{2} 0 & 0 & 0 a - x & x & x \end{matrix}$
$\Rightarrow K_{P} = [N H_{3}] [H_{2} S] = x^{2}$
$x^{2} = 64 a t m^{2}$
$x = 8 a t m$
total pressure at equilibrium $= 8 + 8 = 16 a t m$