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Byju's Answer
Standard IX
Chemistry
Stoichiometric Calculations
NH 4 Cl + NaO...
Question
NH
4
Cl+NaOH=
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Solution
NH
4
Cl + NaOH → NaCl + NH
3
+ H
2
O Ammonium chloride react with sodium hydroxide to produce sodium chloride, ammonia and water.
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Q.
∧
∘
m
(
N
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4
O
H
)
is equal to
Q.
∧
∘
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Is NH4Cl soluble in NaOH
Q.
Number of moles of
N
H
3
formed when
0.535
g
of
N
H
4
C
l
is completely decomposed by
N
a
O
H
, is:
N
H
4
C
l
+
N
a
O
H
→
N
H
3
+
N
a
C
l
+
H
2
O
Q.
Number of moles of
N
H
3
formed when 0.535 g of
N
H
4
C
l
+
N
a
C
l
is completely decomposed by
N
a
O
H
, is:
N
H
4
C
l
+
N
a
O
H
→
N
H
3
+
N
a
C
l
+
H
2
O
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