Ni(CO)4 is high spin complex or low spin complex ? It is tetrahedral molecule so it should be high spin complex ( as tetrahedral complex are always high spin )

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Tetrahedral complexes are generally high spin. This is because :

[F e (C N)_{6}]^{- 3}

[F e (H_{2} O)_{6}]^{+ 3}

\begin{matrix} C o l u m n I & C o l u m n 2 & C o l u m n 3 (I) & [N i (C O)_{4}] & (i) & s p^{3} & (P) & D i a m a g n e t i c (H i g h s p i n) (I I) & [P t C l_{4}]^{2 -} & (i i) & s p^{3} d^{2} & (Q) & P a r a m a g n e t i c (H i g h s p i n) (I I I) & [N i (C O)_{4}] & (i i i) & d s p^{2} & (R) & D i a m a g n e t i c (L o w s p i n) (I V) & K_{2} [C o (C N)_{4}] & (i v) & d^{2} s p^{3} & (S) & P a r a m a g n e t i c (L o w s p i n) \end{matrix}

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