Question

Nickel atom can lose two electrons to form $N{i}^{2+}$ ion. The atomic number of nickel is 28. From which orbital it can lose two electrons?

• A. $N{i}^{2+}={\left[Ar\right]}^{18}3d^{8}4s^2$ , To form $N{i}^{2+}$ ion, it will lose electrons from 4s
• B. $N{i}^{2+}={\left[Ar\right]}^{18}3d^{8}4s^2$, To form $N{i}^{2+}$ ion, it will lose electrons from 3d
• C. both from 3d and 4s
• D. none of the above

Answer 1

The correct option is A $N{i}^{2+}={\left[Ar\right]}^{18}3d^{8}4s^2$ , To form $N{i}^{2+}$ ion, it will lose electrons from 4s

The electronic configuration of Ni atom is ${\left[Ar\right]}^{18}3d^{8}4s^2$. To form $N{i}^{2+}$, it will lose two electrons from 4s orbital to form $N{i}^{2+}$ with electronic configuration ${\left[Ar\right]}^{18}3d^{8}4s^0$.