Question

Nickel atoms can lose two electrons to form $N{i}^{2+}$ ions. The atomic number of nickel is 28. From which orbital nickel will lose two electrons.

Answer 1

The atomic number of nickel is 28 and the total number of electrons in nickel are 28

The electronic configuration of nickel is as follows:

$Ni=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{8}4s^2$

The electrons will be lost first from 4s orbital of nickel

So, the electronic conifiguration of $N{i}^{2+}$

$N{i}^{2+}=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^8{45}^0$

Hence, nickel will lose 2 electrons from 4s orbital