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Empirical & Molecular Formula

Nickel forms ...

Question

Nickel forms a compound with carbon monoxide, $N i_{x} (C O)_{y}$ . To determine its formula, you carefully heat a $0.0973$ g sample in air to convert the nickel to $0.0426$ g of $N i O$ and the $C O$ to $0.100 g C O_{2}$ . If the empirical formula is of the form $N i_{x} (C O)_{y} [N i = 58.7]$ , then $x + y$ is :

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Solution

The sample is heated in air to convert the $N i$ to $N i O$ and $C O$ to $C O_{2}$ .
The reaction is as shown below:
$N i_{x} (C O)_{y} ⟶ x N i O + y C O_{2}$
$(58.7 x + 30 y) 74.7 x 44 y$

$\frac{74.7 x}{44 y} = \frac{0.0426}{0. 10}$

$∴ \frac{x}{y} = 0.25 = \frac{1}{4}$
Thus, $e m p i r i c a l f o r m u l a i s = N i (C O)_{4}$
Hence, $x + y = 1 + 4 = 5$

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