Question

Nine-fifth of the temperature in centrigrade ($C$) of a body plus 32${}^o$ is equal to the temperature of the same body in Fahrenheit ($F$). Find $F$, when $C={55}^o$

• A. ${131}^o$
• B. ${120}^o$
• C. ${140}^o$
• D. ${166}^o$

Answer 1

The correct option is A ${131}^o$

According to the given condition,

$F=\frac{9}{5}C+32$

$\therefore F=\frac{9}{5}\left(55\right)+32$

$=99+32$ $={131}^o$