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Question

Nine hundred distinct n digit numbers are to be formed using only the three digits 2,5 and 7. the smallest value of n for which this is possible is

A
4
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B
8
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C
7
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D
9
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Solution

The correct option is B 7
Using 2,5 and 7 with repetition, each place of n digits number can be chosen in 3 ways. So total of n digit number is equal to =3×3×3×....×3(ntimes)=3n
According to the question, 3n9003n2100n25n7

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