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Question

Nine identical wires each of diameter d and length L are connected in parallel. The combination has the same resistance as a single similar wire of length L but whose diameter is ____.


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Solution

Find the diameter:

In parallel,

1Rnet=1R1+1R2+1R3+....+1R9

All wires are identical so resistance will be equal.

So 1Rnet=1R+1R+1R+....+1R

1Rnet=9R

R=LA

A=πr2

A=πd24r=d2

So Rnet=L×4rd2×9

NowRnet=LA

Let the diameter of the new wire is D

A'=πD24

So Rnet=L×4rD2

According to the question,

L×4rD2=L×4rd2×9

D2=9d2

D=3d

Nine identical wires each of diameter d and length L are connected in parallel. The combination has the same resistance as a single similar wire of length L but whose diameter is 3d.


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