Nitrate ion on reacting with conc. $H_{2} S O_{4}$ gives:

nitrogen dioxide

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nitrogen pentaoxide

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nitrous oxide

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None of the above

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Solution

The correct option is A nitrogen dioxide
To find: Products of reaction of nitrate ion with conc $H_{2} {S O}_{4}$
$N {O_{3}}^{-} + H_{2} S O_{4} \to H N O_{3} + S {O_{4}}^{2 -}$
$H N O_{3} \to N O_{2} + H_{2} O$

Nitrate ions reacts with sulphuric acid to form nitrogen dioxide which in presence of water dissolves to form nitric acid.

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