Nitric acid can be produced by NH3 in three steps process- i 4NH3g-5O2g - 4NO g-6H2Og ii 2NOg-O2g - 2NO2g iii 3NO2g-H2Ol - 2HNO3aq-NOg - yield of i- ii and iii are 50 - 60 - and 80 - respectively- then what volume of NH3g at 1 atm and 0 - C required to produce 1575 g of HNO3-

The correct option is C 3500 Moles of NO_2 required =(1575/63) × nbsp;3/2× nbsp;1/0.8=46.875 .Moles of NO required =46.875/0.60 .M ...

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Stoichiometric Calculations

Nitric acid c...

Question

Nitric acid can be produced by $N H_{3}$ in three steps process:
$(i) 4 N H_{3} (g) + 5 O_{2} (g) \to 4 N O (g) + 6 H_{2} O (g)$
$(i i) 2 N O (g) + O_{2} (g) \to 2 N O_{2} (g)$
$(i i i) 3 N O_{2} (g) + H_{2} O (l) \to 2 H N O_{3} (a q) + N O (g)$
$%$ yield of $i, i i$ and $i i i$ are $50 %, 60 %$ and $80 %$ respectively, then what volume of $N H_{3} (g)$ at $1 a t m$ and $0^{\circ} C$ required to produce $1575 g$ of $H N O_{3}$ ?

156.25

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350

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3500

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None of theses

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Similar questions

4 N H_{3} (g) + 5 O_{2} (g) \to 4 N O (g) + 6 H_{2} O (g) (i)

2 N O (g) + O_{2} (g) \to 2 N O_{2} (g) (ii)

3 N O_{2} (g) + H_{2} O \to 2 H N O_{3} (a q) + N O (g) (iii)

N H_{3}

H N O_{3}

4 N H_{3} (g) + 5 O_{2} (g) \to 4 N O (g) + 6 H_{2} O (g) (i)

2 N O (g) + O_{2} (g) \to 2 N O_{2} (g) (ii)

3 N O_{2} (g) + H_{2} O \to 2 H N O_{3} (a q) + N O (g) (iii)

N H_{3}

H N O_{3}

{4 N H}_{3 (g)} + {5 O}_{2 (g)} \to {4 N O}_{(g)} + {6 H}_{2} O_{g}

{2 N O}_{g} + O_{2 (g)} \to {2 N O}_{2 (g)}

{3 N O}_{2 (g)} + H_{2} O_{(g)} \to {2 H N O}_{3 (a q)} + {N O}_{(g)}

4 N H_{3} (g) + 5 O_{2} (g) \to 4 N O (g) + 6 H_{2} O (l) Δ H = - 904 k J . . . (1)

2 N O (g) + O_{2} (g) \to 2 N O_{2} (g) Δ H = - 112 k J . . . (2)

3 N O_{2} (g) + H_{2} O (l) \to 2 H N O_{3} (a q) + N O (g) Δ H = - 140 k J . . . (3)

(i n kJ/mole)

4 N H_{3} + 5 O_{2} (g) C a t a l y s t - ---- \to P t / R h 4 N O (g) + 6 H_{2} O (g) . . . (i)

2 N O (g) + O_{2} (g) 1120 K - --- \to 2 N O_{2} (g) . . . (i i)

3 N O_{2} (g) + H_{2} O (l) \to 2 H N O_{3} (a q) + N O (g) . . . (i i i)

68.5 %

98 %

170 k g

N H_{3}

H_{2} O (l)

1^{s t}

1 \frac{g}{m l}

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