Nitrobenzene on reduction using zinc in alkaline medium results in ′X′. The number of sigma (σ) and pi (π) bonds in ′X′ is:
A
24σ,7π
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B
24σ,6π
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C
27σ,7π
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D
27σ,6π
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Solution
The correct option is C27σ,7π As the compound formed by the reduction of nitro benzene by zinc in alkaline medium gives the Azobenzene and there are 27σ , 7π bonds. Therefore C is the correct option.