Nitrobenzene on reduction with Zn dust and aqueous $N H_{4} C l$ forms :

C_{6} H_{5} N H_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{6} H_{5} N O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{6} H_{5} N = N C_{6} H_{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{6} H_{5} N H O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $C_{6} H_{5} N H_{2}$
Zn dust and aqueous $N H_{4} C l$ is mild reducing agent reducing nitro group to amine.

Suggest Corrections

Similar questions

N H_{4} C l / Z n

H_{2} S O_{4} / N a_{2} C r_{2} O_{7}

Z n / N H_{4} C l

1.23

Z n + N H_{4} C l

Join BYJU'S Learning Program