Nitroethane on reduction with $S n / H C l$ gives:

C_{2} H_{6}

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C_{2} H_{5} N H_{2}

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C_{2} H_{5} O H

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None of the above

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Solution

The correct option is B $C_{2} H_{5} N H_{2}$
The products formed are as follows:
$C_{2} H_{5} N O_{2} S n + H C l - ---- \to C_{2} H_{5} N H_{2}$
$M e t a l = F e / S n$
Hence b is the correct option.

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