Nitrogen atom has three unpaired electron because it follows:

Hund' s rule

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Heisenberg' s uncertainty principle

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Pauli' s exclusion principle

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Aufbau principle

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Solution

The correct option is A Hund' s rule
As per Hund’s rule, electron in a subshell cannot pair up unless each orbital is filled singly. Hence in nitrogen, unless each of the p orbitals are filled singly by electrons, electrons do not pair up as a result of which it has 3 unpaired electrons.

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Similar questions

If carbon atom has electronic configuration 1 $s^{6}$ , it would have energy lower than that of the normal ground state configuration 1 $s^{2}$ 2 $s^{2}$ 2 $p^{2}$ . Yet 1 $s^{6}$ is not observed because it violates

Q. If the nitrogen atom had an electronic configuration of

1 s^{7}

it would have lower energy than that of the normal ground state configuration

1 s^{2}, 2 s^{2}, 2 p^{3}

because the electrons would be closer to the nucleus.

1 s^{7}

is not observed because it violates:

Q. If nitrogen atom had an electronic configuration of

1 s^{7}

, it would have energy lower than it’s normal ground state configuration of

1 s^{2} 2 s^{2} 2 p^{3} . Y e t, 1 s^{7}

is not observed as it violates:

Nitrogen has the electronic configuration $1 s^{2}, 2 s^{2} 2 p_{x}^{1} 2 p_{y}^{1} 2 p_{z}^{1}$ and not $1 s^{2}, 2 s^{2} 2 p_{x}^{2} 2 p_{y}^{1} 2 p_{z}^{0}$ which is determined by

Q. If carbon has electronic configuration

1 s^{6}

, it would have lower energy than that of the normal ground state configuration

1 s^{2} 2 s^{2} 2 p^{2}

, because the electrons would be closer to the nucleus. Yet

1 s^{6}

is not observed, since it violates

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Nitrogen atom has three unpaired electron because it follows:

The correct option is A Hund' s ruleAs per Hund’s rule, electron in a subshell cannot pair up unless each orbital is filled singly. Hence in nitrogen, unless each of the p orbitals are filled singly by electrons, electrons do not pair up as a result of which it has 3 unpaired electrons.

The correct option is A Hund' s rule
As per Hund’s rule, electron in a subshell cannot pair up unless each orbital is filled singly. Hence in nitrogen, unless each of the p orbitals are filled singly by electrons, electrons do not pair up as a result of which it has 3 unpaired electrons.