Question

Nitrogen form $N_2$ but phosphorous when forms $P_2$ gets readily converted into $P_4$ because : -

• A. Triple bond present between phosphorous atom
• B. $p_{\pi }{p}_{\pi }$bonding is weak
• C. $p_{\pi }{p}_{\pi }$bonding is strong
• D. Multiple bond form easilly

Answer 1

The correct option is B $p_{\pi }{p}_{\pi }$bonding is weak

Phosphorus is unable to form $p\pi -p\pi$ bonds due to larger atomic size. So, $P$ atom is linked with $P$ atoms using $3$ sigma bonds. On the other hand, Nitrogen forms $1-\sigma$ and $2-\pi$ bonds i.e., triple bonds and exists as diatomic molecules.