Question

Nitrogen forms $N_2$ but phosphorous when forms $P_2$ gets readily converted into $P_4$ because:

• A. Triple bond present between phosphorous atom
• B. $p_{\pi }-p_{\pi }$ bonding is weak
• C. $p_{\pi }-p_{\pi }$ bonding is strong
• D. Multiple bond form easily

Answer 1

The correct option is B $p_{\pi }-p_{\pi }$ bonding is weak

Phosphorudue is unable to form $p\pi -p\pi$ bonds due to larger atomic size. So, P atom is linked with P atom using 3 sigma bonds. On the other hand, nitrogen forms $1-\sigma \text{and}2-\pi$ bonds i.e., triple bond and exists as diatomic molecule.